Solve the simultaneous equations: 5x + y = 21 and x - 3y = 9

label equation 5x + y = 21 as (1) and equation x - 3y = 9 as (2) multiply equation (2) by 5 to get : 5x - 15y = 9 (3) then subtract equation (1) from equation (2) in order the eliminate the x variable -16y =24 solve for y: y = -3/2 then substitute the value for y =-3/2 into the first equation and solve for x to determine: x=9/2

SG
Answered by Shruti G. Maths tutor

2427 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve these simultaneous equations: 2x + 3y = 19 and x + 4y = 17.


Solve 3x + 10 = 10(2x-5)


How do you use the pythagoras equation?


How do you calculate ratios? Example question: 'White paint costs £2.80 per litre, Blue paint costs £3.50 per litre, White paint and blue paint are mixed in the ratio 3:2. Work out the cost of 18 litres of the mixture [4 marks]' AQA Mathematics (8300)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning