solve the simultaneous equation x^2 + 2y = 9 , y - x = 3

First we need to find a value for x in terms of y , this can be done by rearranging the second equation y - x = 3 to give x = y - 3. This equation is then substituted into the first equation so that everything is in terms of y giving us (y - 3)^2 + 2y = 9. We then multiply out the brackets to give us y^2 - 6y + 9 + 2y = 9 this simplifies to y^2 - 4y = 0. Therefore y = 0 to find the x value we sub this value of y into the second equation to give 0 - x = 3 and solve to find x = -3

SB
Answered by Sara B. Maths tutor

2662 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

GCSE: How do you find the bearing of point B from A?


How do I factorise x^2 + 8x + 15?


Solve these two equations simultaneously: 7x + y = 1 and 2x^2 - y = 3.


Kelly is trying to work out the two values of w for which 3w - w^3 = 2 Her values are 1 and -1 Are her values correct? You must show your working.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences