Differentate sin(x^2+1) with respect to x

y = sin(x2+1) In general, the chain rule is: dy/dx = f(g(x)) = df/dg * dg/dx Applying this to y: dy/dx = d(sin(x2+1))/d(x2+1) * d(x2+1)/dx = cos(x2+1) * (2x) = 2xcos(x2+1)

Answered by Maths tutor

3170 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate y=x*ln(x^3-5)


Solve algebraically: 2x - 5y = 11, 3x + 2y = 7


Show how to derive the quadratic formula


Find the tangent to the curve y=x^3+3 at the point x=1.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning