Solve the simultaneous equations 5x + 3y = 24 and 3x - 4y = 26

Ok, so here are the equations5x+3y=243x-4y=26So let's multiply the first equation by 3, which gives us:15x+9y=72Now let's multiply the second equation by 5, which gives us:15x-20y=130So we're now left with:15x+9y=7215x-20y=130Let's rearrange both of these equations to make 15x the subject. So now we're left with:15x = 72-9y15x= 130+20yNow we can compare these two equations, to give us:72-9y=130+20y (=15x)If we rearrange this new equation, we find that:20y + 9y = 72 - 13029y = -58y = -2Since we now have a value for y, we can substitute this back into 5x + 3y = 245x + 3(-2) = 245x -6 = 245x = 30x = 6So, are final answer is x = 6 and y = -2

WS
Answered by William S. Maths tutor

11350 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify fully (3x^2-8x-3)/(2x^2-6x)


The equation of the line L1 is y = 3x – 2 The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel.


Find the values of a, b and c in the equation: (5x + 3)(ax + b) = 10x^2 + 11x + c.


Solving simultaneous questions, e.g. 3x + y = 11 and 2x + y = 8


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning