Given that f(x) = x^2 (3x - 1)^(1/2) find f'(x)
This is an example of a question using the product rulelet u = x2 and v = (3x - 1)1/2then u' = 2x and v' = 3 X 1/2 (3x - 1)-1/2 using the product rule we get f'(x) = x2 X 3/2 (3x - 1)-1/2 + (3x - 1)1/2 X 2xwhich is simplified to = x(15x - 4) / [2(3x - 1)1/2]
Related Maths A Level answers
All answers ▸Express 6cos(2x)+sin(x) in terms of sin(x). Hence solve the equation 6cos(2x) + sin(x) = 0, for 0° <= x <= 360°.
The General Form of the equation of a circle is x^2 + y^2 + 2gx +2fy + c = 0. Find the centre of the circle and the radius of the circle in terms of g f and c.
y = 4x^3 - 5/x^2 find dy/dx
How would you express (11+x-x^2)/[(x+1)(x-2)^2] in terms of partial fractions?