Given that f(x) = x^2 (3x - 1)^(1/2) find f'(x)
This is an example of a question using the product rulelet u = x2 and v = (3x - 1)1/2then u' = 2x and v' = 3 X 1/2 (3x - 1)-1/2 using the product rule we get f'(x) = x2 X 3/2 (3x - 1)-1/2 + (3x - 1)1/2 X 2xwhich is simplified to = x(15x - 4) / [2(3x - 1)1/2]
