Find the equation of the line that passes through (2, 4) and (7, -11)
Step 1) Write out the general equation of a straight line: y = mx + c where m is the gradient and c is where the line intersects the y-axis. Step 2) Find the gradient: m = change in y / change in x, m = (-11-4) / (7-2), m = -15 / 5 m = -3 Step 3) Find c: This can be done by substituting in co-ordinates of either of the points that the line passes through into the equation y = -3x + c, 4 = -3*2 + c, c = 10 Step 4) Write out the equation: y = -3x + 10
RG
Related Maths GCSE answers
All answers ▸a.) simplify and expand (x+3)(2x+5) b.) differentiate (x+3)(2x+5) c.) where does this function intercept the x and y axis? d.) does this function have any turning points? if so where?
Prove n^3-n is multiple of 6 for all n
Solve x/2 + 3x/(x+) = 1
what is the gradient and y intercept of the equation y=7x+7