Find the equation of the line that passes through (2, 4) and (7, -11)

Step 1) Write out the general equation of a straight line: y = mx + c where m is the gradient and c is where the line intersects the y-axis. Step 2) Find the gradient: m = change in y / change in x, m = (-11-4) / (7-2), m = -15 / 5 m = -3 Step 3) Find c: This can be done by substituting in co-ordinates of either of the points that the line passes through into the equation y = -3x + c, 4 = -3*2 + c, c = 10 Step 4) Write out the equation: y = -3x + 10

RG
Answered by Romily G. Maths tutor

3308 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve (2x^2 - 3x - 14)/(x^2 + 6x + 8) = -6/(x+3).


Factorise the expression: 8x + 32


Find the solutions of the equation x^2 - 2x - 8 =0


Solve the simultaneous equations: 3x + 2y =4 4x + 5y =17


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences