Find the stationary points on the curve: y = x^3 + 3x^2 +2x+5

Firstly differentiate the function:f(x) = x3 + 3x2 + 2x + 5 (function)f'(x) = 3x2 + 6x + 2 (gradient function)
Stationary points are points where the graph has a gradient of zero
3x2 + 6x + 2 = 0
In order to find the x-values we need to solve the quadratic equation:a = 3, b = 6, c =2 ----> sub into the equation (will explain on whiteboard)Use quadratic equation to find x = -1 +/- root(3)/3
Finally sub in the x - values into the initial function to find the corresponding y values. Done!

NC
Answered by Nicolas C. Maths tutor

5795 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Prove the property: log_a(x) + log_a(y) = log_a(xy).


How do you find the x co-ordinates of the stationary points of a curve with the equation y = 10x - 2x^2 - 2x^3


∫ 4/x^2+ 5x − 14 dx


Consider a differential equation where dx/dt = -axt. Find an equation for x(t).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences