Find the stationary points on the curve: y = x^3 + 3x^2 +2x+5
Firstly differentiate the function:f(x) = x3 + 3x2 + 2x + 5 (function)f'(x) = 3x2 + 6x + 2 (gradient function)
Stationary points are points where the graph has a gradient of zero
3x2 + 6x + 2 = 0
In order to find the x-values we need to solve the quadratic equation:a = 3, b = 6, c =2 ----> sub into the equation (will explain on whiteboard)Use quadratic equation to find x = -1 +/- root(3)/3
Finally sub in the x - values into the initial function to find the corresponding y values. Done!
NC
Related Maths A Level answers
All answers ▸Find the turning point of y = x + 1 + 4/x2 and describe the nature of the turning point
How do I use numerical methods to find the root of the equation F(x) = 0?
Find an equation of the circle with centre C(5, -3) that passes through the point A(-2, 1) in the form (x-a)^2 + (y-b)^2 = k
Integrate 5cos(3x - 1) with respect to x