Calculate the indefinite integral of xsinx
They key is to integrate by parts, set u = x, u' = 1, v' = sinx, v = -cosx
So, integral(xsinx) =uv - integral(u'v)+c = -xcosx - integral(-cosx) +c = -xcosx +sinx + c
which is the answer
SL
They key is to integrate by parts, set u = x, u' = 1, v' = sinx, v = -cosx
So, integral(xsinx) =uv - integral(u'v)+c = -xcosx - integral(-cosx) +c = -xcosx +sinx + c
which is the answer
