Using logarithms solve 8^(2x+1) = 24 (to 3dp)

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Using the laws of logs you can see that if you log both sides of the equation you get: 

(2x+1)*log(8) = log(24) 

Dividing both sides of the equation by log(8) you get: 

2x+1 = log(24)/log(8)

Then it is a simple case of solving for x: 

x = 0.5*(((log(24)/log(8))-1)

x = 0.264

Graham R. A Level Maths tutor, GCSE Maths tutor, A Level Physics tuto...

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