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Use the chain rule to differentiate y=(x-3)^(-3)

Hint: the chain rule states that for y=u(x) ^a, the derivative will be dy/dx = dy/du * du/dx

So we just need to find dy/du and du/dx!

In this case u(x)=x-3, so du/dx = 1.

from y=u^(-3), dy/du = -3u^(-4).

This means we know dy/dx = -3u^(-4) * 1

Converting from u to x, we get dy/dx = -3 (x-3)^(-4)  .... done! 

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