Differentiate y = x(x+3)^4

 To differentiate this function we use the product rule. In the product rule we, leave the first alone, differentiate the second, and leave the second alone, differentiate the first.                                                                                                                  Say y = U * V (U and V are both functions of x)                                                                                                                      Then in general we have y' = U dV/dx + V dU/dx For this example we have; y' = x * d/dx (x+3)4 +  (x+3)4 d/dx x                      y' = x * 4 * (x+3)3 * 1 +  (x+3)4  * 1                                                                                                                                        When differentiating bracketed term we start differentiating outside the brackets and work our way in, therefore initially treating the brackets like a single term then accounting for the terms inside the brackets. To simplify the final expression we now take out the common factor.                                                                                                                                                       y' =  (x+3)3 [4x + (x+3)]                                                                                                                                                         Therefore, y' = (x+3)3 (5x+3)

Answered by Harry H. Maths tutor

2796 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The line l1 has equation y = −2x + 3. The line l2 is perpendicular to l1 and passes through the point (5, 6). (a) Find an equation for l2 in the form ax + by + c = 0, where a, b and c are integers.


Given that 9 sin^2y-2 sin y cos y=8 show that (tany - 4)(tany + 2)= 0


Integrate 3x^2+cos(x) with respect to x


Find the equation of the tangent to the curve y = 2x^2 + x - 1 at the point where x = 1.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy