Solve the following simultaneous equations to find the values of x and y: 3y - 7x = 15 & 2y = 4x + 12

Equation one: 3y - 7x = 15

- Double it and re arrange   3y - 7x = 15 goes to 3y = 7x + 15 goes to 6y = 14x + 30 we name this equation 3

Equation two: 2y = 4x +12

- Triple it.  so..6y = 12x + 36 we name this equation 4

Now we minus equation 4 from equation 3

                                    6y - 6y = 14x -12x + 30 - 36

which goes to

                                  0 = 2x -6

We can now rearrange this new equation

                                 2x = 6 and therefore x = 3

To find y we know just input our value of x into either of the original equations

                                2y = 4(3) + 12

Rearranging the equation we get

                                2y = 24 and therefore y = 12

so our final answer is

                               x = 3    y = 12

IP
Answered by Imogen P. Maths tutor

3972 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

If two linear equations, y = x + 4 and y = 2x + c, intersect at x = 1, find c.


Solve these simultaneous equations algebraically: y=2x^2 - 7x + 4 & y=4x-1


Solve 14-x = 4(1+x)


Quadratic Equations and factorising


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences