Solve the following simultaneous equations to find the values of x and y: 3y - 7x = 15 & 2y = 4x + 12

Equation one: 3y - 7x = 15

- Double it and re arrange   3y - 7x = 15 goes to 3y = 7x + 15 goes to 6y = 14x + 30 we name this equation 3

Equation two: 2y = 4x +12

- Triple it.  so..6y = 12x + 36 we name this equation 4

Now we minus equation 4 from equation 3

                                    6y - 6y = 14x -12x + 30 - 36

which goes to

                                  0 = 2x -6

We can now rearrange this new equation

                                 2x = 6 and therefore x = 3

To find y we know just input our value of x into either of the original equations

                                2y = 4(3) + 12

Rearranging the equation we get

                                2y = 24 and therefore y = 12

so our final answer is

                               x = 3    y = 12

IP

Related Maths GCSE answers

All answers ▸

2x + 4 > 16


Consider a right-angled triangle with an inside angle of 30° and a hypotenuse of 8cm. Calculate the length of the opposite side to the 30° angle.


If the probability of picking a red ball out of bag A is 2/5 and the probability of picking a red ball out of bag B is 3/7, what is the chance that you will pick exactly 2 red balls if you pick 2 balls from A and 1 ball from B? The balls are not replaced.


How to make something the subject of the formula?