Solve the simultaneous equations: 3x+5y=3 and 6x+6y=10

(1): 3x+5y=3

(2): 6x+6y=10

Multiply number one by two to give a common factor of 6x in both equations.

(3)=[2*(1)]- 6x+10y=6

Take away equation (2) from equation (3) to leave us with only y's and numbers so that we can solve a value of y.

(3)-(2): 4y=-4

Divide both sides by 4

y=-1

With this value sub back into an original equation wherever there is a y, this does not matter if you choose (1) or (2) as it will give you the same value.

(1): 3x+5y=3

(1): 3x+5(-1)=3

(1): 3x-5=3

(1): 3x=8

(1): x=8/3

(1): x=2.66666666

(1): x=2.67

Final values

y=-1; x=8/3 or 2.67

EO
Answered by Ethan O. Maths tutor

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