Simplify and solve for x. log(x+1)+log 5=2. Note, log is the natural log in this case

so lets deal with 2 first. We can express 2 in terms of log5 by the laws of logs. nlogx=logx^n. re-writing 2 as 2log5=log25 we now have log(x+1)+log5=log25. lets apply a different log law: log(a)-log(b)=log(a/b). Therefore we get log(x+1)=log(25)-log(5)=log(25/5)=log(5). Now we can cancel the logs to get x+1=5 and now solve algebraically giving x=4

LM
Answered by Liam M. Maths tutor

6806 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I integrate and differentiate 1/(x^2)?


How would you differentiate f(x) = 2x(3x - 1)^2 using the chain rule?


What is the indefinite integral of (x^4)*(-sin(x)) dx


Express (3x^2 - 3x - 2)/(x-1)(x-2) in partial fractions


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning