Find the set of values for which x^2 - 7x - 18 >0

To see where the graph is greater than zero, we start by finding where it meets zero. By factorising (x^2 - 7x - 18), we find it equals (x-9)(x+2). The expression equals zero at the points x = 9 and x = -2. Now we need to know the shape of the graph. First, we can see the x^2 term is positive, which means the curve is a 'bowl' shape. Alternatively, we can work out if an x value in between -2 and 9 works for the inequality. Say x=0. 0^2 - 7(0) - 18 = -18. This is less than 0 so does not satisfy the inequality. Now we know the graph is more than zero outside of the interval between x=-2 and x=9. Therefore x < -2 or x > 9.

CW
Answered by Charlotte W. Maths tutor

17093 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the minimum value of the function, f(x)= x^2 + 5x + 2, where x belongs to the set of Real numbers


How would I go about drawing the graph of f(x) = sin(x)/(e^x) for -π≤x≤2π?


A curve C has equation 2^x + y^2 = 2xy. How do I find dy/dx for the curve C?


A line has equation y = 2x + c and a curve has equation y = 8 − 2x − x^2, if c=11 find area between the curves


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning