Solve the differential equation dy/dx=(y^(1/2))*sin(x/2) to find y in terms of x.

Here, we must first rearrange our equation so all x terms are on one side and all y terms are on the other. Multiplying both sides by dx and diving both by y^(1/2) gives us y^(-1/2)dy = sin(x/2)dx, which is a directly integrable equation. Integrating both sides, we get 2y^(1/2) = -2cos(x/2) + c, where c is some arbitrary constant of integration. Rearranging to find y, we get y=(-2cos(x/2) + A)^2, where A=c/2.

AJ
Answered by Alex J. Maths tutor

7012 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Consider the unit hyperbola, whose equation is given by x^2 - y^2 = 1. We denote the origin, (0, 0) by O. Choose any point P on the curve, and label its reflection in the x axis P'. Show that the line OP and the tangent line to P' meet at a right angle.


How do I invert a 2x2 square matrix?


express the following fraction in the form of m + (n)^1/2. the fraction is ((3*(5)^1/2)^2 - 7)/(3 + 7*(5)^1/2). where m,n are real numbers.


A curve is given by the equation y = (1/3)x^3 -4x^2 +12x -19. Find the co-ordinates of any stationary points and determine whether they are maximum or minimun points.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning