Solve the differential equation dy/dx=(y^(1/2))*sin(x/2) to find y in terms of x.

Here, we must first rearrange our equation so all x terms are on one side and all y terms are on the other. Multiplying both sides by dx and diving both by y^(1/2) gives us y^(-1/2)dy = sin(x/2)dx, which is a directly integrable equation. Integrating both sides, we get 2y^(1/2) = -2cos(x/2) + c, where c is some arbitrary constant of integration. Rearranging to find y, we get y=(-2cos(x/2) + A)^2, where A=c/2.

AJ

Related Maths A Level answers

All answers ▸

Find ∫ ( 2x^4 - 4x^(-0.5) + 3 ) dx


Integrate ((7e^(x/2))/4) with respect to x within the bounds of x=0 and x=2. (Basic introduction to definite integration)


Prove that, if 1 + 3x^2 + x^3 < (1+x)^3, then x>0


A curve C has the equation y=5sin3x + 2cos3x, find the equation of the tangent to the curve at the point (0,2)