Can you explain where the "Integration by parts" formula comes from?

Sure. If you remember how to calculate d/dx(uv) then you can understand how integration by parts works. d/dx(uv) = u(dv/dx) + v(du/dx). we can re-arrange this: u(dv/dx) = d/dx(uv) - v(du/dx). Now integrating both sides: |u.dv = uv - |v.du (Where I've used "|" for the integration sign) which is the integration by parts formula.

All you need to do is work out what you use as "u" and "dv", which comes down to experience.

CF
Answered by Christian F. Maths tutor

3825 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

AQA PC4 2015 Q5 // A) Find the gradient at P. B) Find the equation of the normal to the curve at P C)The normal P intersects at the curve again at the point Q(cos2q, sin q) Hence find the x-coordinate of Q.


differentiate y=(3x)/(x^2+6)


If I have a picture of a graph f(x), how can I draw what |f(x)| and 3f(x-2) look like?


How do I find the derivative of two functions multiplied by each other?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning