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A critical analysis is a description of what you, the reader, understand from the text. This shouldn't be from context you have researched or analysis of hypothesis posed by secondary critics, rather it is your analysis of the language, tone and structure of the text and what all of these together mean for the text. What message do they convey? What is the author trying to tell us? Why has she/he used short chapters? What is the significance of repetition in a chapter? And so on. 

It's important to identify the general themes in the texts you are studying. Once you've pulled out the themes, then begin to look for quotes that back up that theme, relate to the theme. Don't rehearse extensive passages, but short lines that you fully understand and can explain or paraphrase. If you can't remember the direct quote, you will not be penalised for paraphrasing.  Once you have your themes and quotes, make mind maps connecting them all. For example, write down the theme of "death" and surround it with a minimum of six quotes that illustrate that theme in the text. 

In order to multiply two matrices together, you must first have that the number of columns in the first matrix must be equal to the the number of rows in the second matrix. So if you wish to multiply matrix A and matrix B, matrix A must have dimensions ( m x n ) whilst matrix B must have dimensions ​​(​n ​x q) . Once you multiply these matrices, the new matrix formed will have dimension m xq​ . (Note that m and q can be equal) For example, matrix A can have dimension 3x2 and matrix B can have dimension 2x4 and so the new matrix will have dimension 3x4. To multiply matrices, you take the first row of Matrix A and multiply its elements by the elements in the first column of Matrix B. You then take the first row of Matrix A and multiply its elements by the elements in the second column of Matrix B. You then keep repeating this process till you have multiplied the elements of the first row of Matrix A to the elements of  every single column of Matrix B. You then take the second row of Matrix A and multiply its elements by the elements of the first column of Matrix B. You then take the second row of Matrix A and multiply it by the elements of the second column of Matrix B. You keep doing this till you have multiplied the second row of Matrix A by every single column of matrix B. You then repeat this process for the third, fourth, fifth (and so on...) row of matrix A.  The following example should make this clear. EXAMPLE ​​Matrix A is ( A B )    and Matrix B is ( 1 2 3 4 )                      ( C D )                                   ( 5 6 7 8)  The dimension of A is 2x2 and the dimension of B is 2x4. Hence, the dimension of the new matrix shall be 2x4. Using the above rules, it should be simple to follow that new matrix is: [ (1a+5b)   (2a+6b)   (3a+7b)  (4a+8b) ​] [ (​1c+5d)   ​(​2c+6d)​   (3c+7d)   (4c+8d) ​] Also note that matrix A multiplied by matrix B does not yield the same result as matrix B multiplied by matrix A. The order in which you multiply matrices matters.

A bromoalkane is a molecule which contains bromine, carbon and hydrogen (and nothing else) and has no carbon-carbon double bonds. An empirical formula gives the simplest ratio of atoms in a molecule. Here's how I'd go about tackling this question:1) Work out the % bromine by mass: 100 - 34.9 - 6.60 = 58.5%, so this is the % mass as we are told the rest of the mass comes from bromine.2) Work out the number of moles of C, H and Br: moles of C = mass/Ar = 34.9/12 = 2.91 (we can use "% mass" as "mass" because we are simply working out a ratio of the atoms relative to each other). Similarly, moles of H = 6.60/1 = 6.60. Moles of Br = 58.5/79.9 = 0.732.3) Work out the whole number ratio of the C:H:Br. You can do this by dividing all the moles by the value for the smallest numeber of moles (i.e. 0.732 moles of bromine). So 2.91 moles of C becomes 3.98 (because 2.91/0.732 = 3.98); 6.60 moles of H becomes 9.02; 0.732 moles of Br becomes 1. As these values are all very close to whole numbers we can simply round them to the nearest, so the ratio of C:H:Br is 4:9:14) You can conclude that the empirical formula of the bromoalkane is C₄H₉Br