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Let u=exp(2x) and v'=cos(8x)From these you can obtain u' and vu=2exp(2x) and v=1/8 sin(8x)Formula: integral(uv'dx)=uv-integral(vu'dx)=1/8 exp(2x)sin(8x)-integral(1/4 sin(8x)exp(2x))=1/8exp(2x)sin(8x)+1/16...
The first thing to recognise is this is a quadratic in disguise, therefore we can rewrite the equation in terms of a new variable y. Where y=x3The equation then becomes 8y2KPAnswered by Kelan P. • Maths tutor7220 Views
Firstly, make sure you are aware of the topics your exam board uses in speaking exams, e.g. 'school', 'holidays' or 'hobbies' and commit to learning some key vocab for each topic. For example, if you're a...
Since the question is a trigonometry question, we shall use integration by recognisation, in which case, we found out that the derivative of sin x is cos x.Therefore by chain rule, we can integrate the fu...
To blame Gorbachev alone is an oversimplification. Reforms may have accelerated the decline of the USSR, but their failure was contingent on long standing economic conditions.Firstly - what were Gor...
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