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6 ∫ e^(2x+1) dx 6 ∫ (1/2)(e^(2x+1))3e^(2x+1) + c

36/x^2 = (36)^0.5/(x^2)^0.56/x = 1/6x

i) dy/dx = 0dy/dx = 6x + 6/x^2 6x + 6/x^2 = 06x^3 + 6 = 0x^3 + 1 = 0x^3 = -1x = -1y = 7(-1, 7)ii) d^2y/dx^2 = 6 - 12/x^3 x = -1 6-12/(-1)^3 = 18>0 therefore, minimum point

First I would set up how i was taught using Pascals Triange. As this is to the power of 4 the numbers across will be 1 4 6 4 1.Then I would multiply each number by the correct power of either (-5x) or (1)...

For expansion:(3x+4)²=9x²+24x+16, go through expansion in online classroom. Now we integrate this using standard polynomial integration rules.
For substitution:
use the sub...