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y = x3- 2xdy/dx = 3x2 -2plugging in x = 2, therefore gradient = 10using the formula to get the equation of a line y -y1=m(x - x1)substitute y1=4 and ...
First thing to do is practice. Practice makes perfect. You are not going to get through your differentiation and integration by doing only a couple of questions on these topics. You need to take one topic...
To differentiate this equation we must use the implicit method, looking at the left side of the equation, to find the differential of the first term we must use the product rule, therefore the differentia...
This can't be differentiated with the usual methods (chain rule, product rule). First we set y = xx, and our objective is to calculate dy/dx in terms of x.To turn this function into more ...
This is a modulus question, asking us to solve for x. As there are two variables in this equation, it is impossible for us to solve for an actual number, so we are asked to answer in terms of a. The easie...
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