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Maths
A Level

A curve has equation y^3+2xy+x^2-5=0. Find dy/dx.

To find the derivative of this, we must differentiate each term with respect to x. This implies d/dx(y^3+2xy+x^2-5=0). We can differentiate each term seperately so d/dx(y^3+2xy+x^2-5=0) is equal to d/dx(y...

MC
Answered by Matthew C. Maths tutor
5068 Views

Differentiate y = x^3 + 2x^2 + 4x + 7

To differentiate you bring the power down and multiply it by any coefficients (numbers in front of the xs) then subtract one from the power 

So x3 becomes 3x2 

2x2...

CS
Answered by Courtney S. Maths tutor
3978 Views

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SV
Answered by Sarah V. Maths tutor
3922 Views

What is the indefinite integral of (x^4)*(-sin(x)) dx

Use integration by parts. Let u = x^4 and let dv/dx = -sin(x). Find du/dx = 4x^3 and fin v = cos(x). Use the equation uv - int (v du/dx) = x^4 cos(x) - 4((x^4/4)*(sin(x)) = x^4 cos(x) - x^4 sin(x) = x^4 (...

SA
Answered by Sarah A. Maths tutor
10077 Views

Simultaneous Equations

So I’ve set out a sheet with a few examples of how to do simultaneous equations. The first method shows a simple graphic representation where you can get an estimate of the solutions, but I then show how ...

LR
Answered by Louis R. Maths tutor
3513 Views

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