Differentiate y = x^3 + 2x^2 + 4x + 7

To differentiate you bring the power down and multiply it by any coefficients (numbers in front of the xs) then subtract one from the power 

So x3 becomes 3x2 

2x2 becomes 2*2x2-1 = 4x

4x becomes 4*1x1-1 = 4

7 is a constant so can't be differentiated

Final answer: 3x2 + 4x + 4

CS
Answered by Courtney S. Maths tutor

3559 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How would you show that a vector is normal to a plane in 3D space?


Given that y = 3x(^2) + 6x(^1/3) + (2x(^3) - 7)/(3(sqrt(x))) when x > 0 find dy/dx


What is the integral of (cos(x))^2?


Show that (sec(x))^2 /(sec(x)+1)(sec(x)-1) can be written as (cosec(x))^2.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences