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1. Differentiate the Equation of the curve to find the gradient: y'=3x^2
2. The gradient of the tangent is found by substituting x=1 into y'=3x^2: Gradient of tangent=3
3. N...
We are given the substitution to use, so the first step is to differentiate "u" with respect to x.
du/dx = -sin(x)
Now, to replace the "dx&q...
As we are differentiating a product (two things times together) we can use the product rule which is if:
y = u(x)v(x)
then
...
When we integrate a function we must first raise the power of x in each term by one. The first term therefore becomes x^(5/2). The second term can be thought of as x^0 which we know that any number to ...
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