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You should write a^x as (e^lna)^x = e^xlna . ln(a) is a constant, so use the chain rule to differentiate this: lna(e^xlna) = lna(a^x)

a x b = 8i + 24j - 42k

Here, we are asked to differentiate with respect to x. That is what dy/dx stands for. So, we are only concerned with the terms involving x; that is x^3 and 2x. To differentiate you need to time x (and its...

So our first priority is to get all the Xs onto on side and add them together. But we cant do that just yet because of 3(x-2).

so lets move all X values to the left of the equation 3(x-2) + 2x <...

1/(x(1-3x))= A/x+ B/(1-3x) 1= A(1-3x) + B(1-3x)

when x=0    1=A

when x= 1/3     1=B/3 so B=3

1/(x(1-3x))= 1/x + 3/(1-3x)