Top answers

Maths
A Level

Find the gradient of a curve whose parametric equations are x=t^2/2+1 and y=t/4-1 when t=2

Remember that the gradient of a curve is expressed as dy/dx. This can be solved by using the chain rule:

dy/dx = dy/dt*dt/dx. The dt in the denominator of the first term, and the numerato...

AS
Answered by Abigail S. Maths tutor
8995 Views

Where does the geometric series formula come from?

Rearranging the terms of the series into the usual "descending order" for polynomials, we get a series expansion of:  

axn-1 +........ax + a

A basic pro...

NA
Answered by Naheem A. Maths tutor
4681 Views

The points P (2,3.6) and Q(2.2,2.4) lie on the curve y=f(x) . Use P and Q to estimate the gradient of the curve at the point where x=2 .

To answer this question you will need to recall the formula for the gradient of a straight line. Cordinates are written in the form (x​1,x2​) and (y1,​y2​)...
AY
Answered by Abdulmuminu Y. Maths tutor
6286 Views

Integrate this funtion f'(x)=2x +4 with respect to x (C1 integration)

Solution to Answer:

y= (2x^2)/2 + 4x + C

Therefore:

y= x^2 + 4x + C

Steps on how to do C1 Integration

y = ...

SQ
Answered by Seair Q. Maths tutor
6492 Views

What is the second derivative used for?

First of all, "second derivative", d2y/dx2, is what you get when you differentiate the first derivative (dy/dx).

The second derivative can be used as an ea...

KT
41692 Views

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