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Maths
GCSE

What is 16^(3/2)

The rule for simplifying indices is to take them one at a time, so separate the problem into 16^(1/2)^3, which is 4^3, which is 64.

JB
Answered by Jonah B. Maths tutor
3426 Views

Let a = 4b + 5(c - b). Find the value of c when a = 8 and b = 7.

a = 4b + 5(c - b) - question8 = (4*7) + 5(c - 7) - insert values given in question8 = 28 + 5c -35 - multiply and expand brackets8 - 28 + 35 = 5c - take away 28 from the left and right-hand side of the equ...

GH
Answered by George H. Maths tutor
3895 Views

Solve the equation 18x^2-3x=6

First put the equation into the correct form by setting it to 0:18x^2-3x-6=0Look for the common factor in the equation and take it out:3(6x^2-x-2)Using the grid method (which I would show on whiteboard) f...

GH
Answered by Grace H. Maths tutor
4576 Views

Expand and simplify (x-4)(2x+3y)^2

Firstly, expand out the (2x+3y)^2 as (2x+3y)(2x+3y).Multiplying each term in the first bracket with each term from the second bracket gives 4x^2+6xy+6xy+9y^2 which simplifies to 4x^2+12xy+9y^2 by adding t...

AW
Answered by Annie-May W. Maths tutor
6042 Views

0.15^2 x (1-0.15)^3 to 2 s.f

BIDMASFirst must donwhat is inside the brackets1-0.15 = 0.85Next must do the indices 0.85^3= 0.6141250.15^2 =0.0225Then multiply0.0225 x 0.614125 = 0.01381781shorten to 2 s.f0.014

FM
Answered by Francesca M. Maths tutor
2593 Views

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