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56 7 x 8 products of 56, 7 is a prime factor 2 x 4 2 is a prime factor 2 x 2 Therefore, 56 as a product of its prime factors is 7 x 2 x 2 x 2 OR 7 x 2^3
(x+4)(x-2)^2(x+4)(x-2)(x-2)(x+4)(x^2-2x-2x+4)(x+4)(x^2-4x+4)x(x^2-4x+4)+4(x^2-4x+4)(x^3-4x^2+4x)+(4x^2-16x+16)x^3-12x+16
To work this out you can either work out the amount of an ingredient needed for one cake then divide the amount you have by this or you can work out how many times the amount needed for 12 cakes goes into...
Substitute y=6x-4 into the equation 3x+6y=15 to eliminate y.You will then have the equation 3x+6(6x-4)=15.The next step is to expand the brackets given 3x+36x -24=15.The next step is to collect like terms...
Sub the values you have been given into the formula provided.v = u +atv = 1 + (-3 x 1/2)Solve the equation you have created, be careful to stick to rules of BIDMAS (or BODMAS)and do the calculation in the...
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