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(4x + 3)/(x + 1) + 2 = 8
Firstly minus the 2 from both sides
(4x + 3)/(x + 1) = 6
Then multiply both sides by the denominator (x + 1)
4x + 3 = 6(x + 1)
Expand the bracke...
Let's solve for x first by substituting y in terms of x.
4x-y=30
y=4x-30
3x+2y=3x+2(4x-30)=3x+8x-60=11x-60
11x-60=17
11x=77
x=7
Now let's solve for y by su...
The 2 equations are: 1) x2 + y2 = 29 2) y-x=3 In this kind of simultaneous equation, you cannot take it away from each other. Instead, you need to substitue. To do so, rearrange the ...
To explain this question, I would first draw a digram of a circle. Then I woud add a chord and create triangles with vrtices at the circumference of the circle which all have the chord as a base. Next, I ...
x2 +3x -4. (x + a) (x - b) x has no co-efficient so each is 1 x. next find two numbers with a product of -4 and a sum of +3. cannot be 2,2 as these numbers have a sum of -4, 0 or +...
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