Top answers

Maths
GCSE

(4x + 3)/(x + 1) + 2 = 8

(4x + 3)/(x + 1) + 2 = 8

Firstly minus the 2 from both sides

(4x + 3)/(x + 1) = 6

Then multiply both sides by the denominator (x + 1)

4x + 3 = 6(x + 1)

Expand the bracke...

JW
Answered by Jessica W. Maths tutor
2789 Views

Solve these pair of simultaneous questions: 3x+2y=17 4x-y=30

Let's solve for x first by substituting y in terms of x.

4x-y=30

y=4x-30

3x+2y=3x+2(4x-30)=3x+8x-60=11x-60

11x-60=17

11x=77

x=7

Now let's solve for y by su...

JY
Answered by Jin-Ho Y. Maths tutor
3969 Views

Solve the simultaneous equations. x^2 + y^2 = 29. y-x = 3

The 2 equations are: 1) x2 + y2 = 29 2) y-x=3 In this kind of simultaneous equation, you cannot take it away from each other. Instead, you need to substitue. To do so, rearrange the ...

PS
Answered by Pallave S. Maths tutor
12540 Views

How do I use the bow-tie circle theorem?

To explain this question, I would first draw a digram of a circle. Then I woud add a chord and create triangles with vrtices at the circumference of the circle which all have the chord as a base. Next, I ...

IT
Answered by Ivana T. Maths tutor
6511 Views

Using the following quadratic equation, find x: x2 + 3x -4

x2 +3x -4. (x + a) (x - b) x has no co-efficient so each is 1 x.  next find two numbers with a product of -4 and a sum of +3.  cannot be 2,2 as these numbers have a sum of -4, 0 or +...

JC
Answered by Jake C. Maths tutor
3538 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences