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Maths
GCSE

How do you approach a simultaneous equations problem?

There should be at least as many simultaneous equations as there are unknown variables - or else you cannot get a numerical answer! Start by trying to eliminate one of the variables. You can multiply the ...

AH
Answered by Annie H. • Maths tutor
3013 Views

ABCD is a square of side 10 cm. Each side of the square is a tangent to the circle. Work out the total area of the shaded regions in terms of . Give your answer in its simplest form.

Here it's best to start this question off by drawing a diagram.

Draw a square with each side having a length of 10cm and a circle which touches each side of the square only once (as eacn side of th...

BM
Answered by Benedicty M. • Maths tutor
15837 Views

What is Pythagoras' Theorem and how is it used in exam questions?

Pythagoras' Theorem is an equation used to give us more information about right angled triangles. The theorem itself looks like this: a2

TD
Answered by Tutor96690 D. • Maths tutor
2868 Views

Solve the simultaneous equation 2x-4y=8 and 3x+3y=-15

Set 2x-4y=8 as equation 1, and 3x+3y=-15 as equation 2. Multiply equation 1 by 3 and equation 2 by 4 so they look like 6x-12y=24 and 12x+12y=-60. Now add the two equations and you get 18x=-36 or x=-2. Sub...

DL
Answered by Daniel L. • Maths tutor
3594 Views

If Q = P / (R (4 – t)), calculate the value of Q when P = 36, R = 3 and t = –2

So seeing as you are given the values for P, R and t, the first thing you need to do is substitute the letters for their given numbers into the equation: Q = (36) / ((3)(4 - (-2)) Now expand out the b...

RB
Answered by Rosie B. • Maths tutor
4034 Views

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