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In order to solve the pair of simultaneous equations, we must find a single set of values for x and y which fulfils both at once. By substituting “x=2-y” into “x2+y2=4”, we obtain a ...
Step 1. Use the formula a2+b2=c2
Step 2. Square a and b to find a2=25 and b2=16
Step 3. Add a2 and b2 to find cERAnswered by Eleanor R. • Maths tutor3731 Views
By completing the square: ax^2 + bx + c = 0 => x^2 + (bx)/a + c/a = 0 (divide both side by a, since a is non-zero) => (x + b/(2a))^2 + c...
First we find two numbers that that add up to -8 and multiply to make 15. In this case the numbers are -3 and -5. This means we can now factorise the quadratic to give (x - 5) (x - 3) = 0. For the above t...
First you need to get the quadratic equation in completed square form. This looks like: (x+p)^2 + q
To put an expression in completed square form you can use this formula: x^2 + 2bx + c = (...
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