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Chemistry
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Part 2: from the empirical formula, calculate the molecular formula if the molecular weight of the substance is 180 g/mol

Molcular weight of CH2O = 30 g/mol
180/30 = 6
Molecular formula = C6H12O6

RT
Answered by Rachael T. • Chemistry tutor
1769 Views

Part 1: Calculate the empirical formula for a substance with the following composition: H 6.71%; C 40.00%; O 53.29%

C = 12 g/molO = 16 g/molH = 1 g/mol
Ratio of C = 40/12 = 3.33Ratio of O = 53.29/16 = 3.33Ratio of H = 6.71/ 1 = 6.71Divide largest value by smallest value = 6.71/3.33 = 2Empirical formula = CH2O

RT
Answered by Rachael T. • Chemistry tutor
1925 Views

Write an equation for the complete combustion of C9H20

Complete combustion is the oxidation of a fuel where the only products exist as CO2 and H2O.
C9H20 + nO2 ==> nCO2 + nH2<...

HF
Answered by Harry F. • Chemistry tutor
6816 Views

Why does hydrogen bonding occur in water?

Hydrogen bonding results from the great difference in electronegativity between oxygen and hydrogen. Electronegativity is the ability of an atom to pull electrons towards itself in a covalent bond. As oxy...

MO
Answered by Myles O. • Chemistry tutor
3453 Views

What are the redox reactions involving carbonyls?

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