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When using the trapezium rule to approximate area underneath a curve between 2 limits, what is the effect of increasing the number of strips used?

Ideally to find the exact area under the curve, we would integrate the function and substitute in the bounds given. However, using the trapezium rule gives an approximation whereby using more trapezia inc...

MM
Answered by Manan M. Maths tutor
9674 Views

Solve the simultaneous equations: 6x + 2y = -3, 4x - 3y = 11

(1)   6x + 2y = -3

(2)   4x - 3y = 11

Multiply by 3 so that the coefficients of y are the same

3 x (1)    18x + 6y = -9

3 x (2)    8x - 6y = 22

Add these 2 together to e...

DH
Answered by David H. Maths tutor
5908 Views

Prove that sin(x)+sin(y)=2sin((x+y)/2)cos((x-y)/2)

We know that 1. sin(a+b) = sin(a)cos(b)+sin(b)cos(a) and 2. sin(a-b) = sin(a)cos(b)-sin(b)cos(a) Add equations 1. and 2. sin(a+b)+sin(a-b) = 2sin(a)cos(b)+sin(b)cos(a)-sin(b)cos(a) = 2sin(a)cos(b) Let x=a...

AV
Answered by Anna V. Maths tutor
35409 Views

The points A and B have coordinates (3, 4) and (7, 6) respectively. The straight line l passes through A and is perpendicular to AB. Find an equation for l, giving your answer in the form ax + by + c = 0, where a, b and c are integers.

For the line passing through A and B: m = (y2-y1)/(x2-x1) = (-6-4)/(7-3) = -5/2

For the perpendicular line: m = -1/(-5/2) = 2/5 

y - y1 = m*(x - x1)  >>  y - 4 = (2/5)*(x - 3)  >>...

DA
Answered by Deji A. Maths tutor
12114 Views

Find the gradient of the tangent to the curve with the equation y = (3x^4 - 18)/x at the point where x = 3

y = (3x- 18)/x

The gradient of a tangent to a curve is equal to dy/dx 

However, we must simplify this equation before we can differentiate it;

y = 3x3 - 18/x =...

RO
Answered by Rachel O. Maths tutor
4508 Views

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