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Fully simplify this equation; 3x^3 - x(3x+36) = 0

The first step is to multiply out the bracket

3x3 - 3x- 36x = 0

Then remove the common factor 3x

3x(x2 - x - 12) = 0

Then factorise the brack...

RO
Answered by Rachel O. Maths tutor
3470 Views

Solve: 7x - 20 = 3x + 4

7x = 3x + 24 4x = 24 x = 24/4 x = 6

AG
Answered by Alex G. Maths tutor
2755 Views

Find the integral between 1 and -2 for (4-x^2-3x^3)

= [4x - 1/3x3 - 3/4x4]1-2 = (4(1) - 1/3(1)3 - 3/4(1)4) - (4(-2) - 1/3(-2)3 - 3/4(-2)4) =(2 11/12) - (-8 + 8/3 - 12) ...

AG
Answered by Alex G. Maths tutor
3504 Views

(x + 2)(x + 3)(x + 6)

First: (x + 2)(x + 3) = x2 + 5x + 6

Second: (x2 + 5x + 6)(x + 6) = x+ 5x2 + 6x + 6x2 + 30x + 36 = x3 + 11x2 + 36x +36<...

UC
Answered by Urma C. Maths tutor
2986 Views

Integrate xcos(x) with respect to x

In order to do this question one has to first recognise that this is a product and thus has to be solved using Integration by parts. Firstly write out the formula: ∫u.dv/dx dx = uv - ∫v. du/dx dx ...

DW
Answered by David W. Maths tutor
4729 Views

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