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dy/dx = u.dv/dx + v.du/dxu = x3, v = ln xdu/dx = 3x2, dv/dx = 1/xdy/dx = 3x2 lnx + x2
We multiply the 2x in the first bracket by everything in the second bracket to give: 2x2-2xWe then multiply the 3 in the first bracket by everything in the second bracket to give: 3x-3Putting 2...
Equation: x2 +4x-5=0 (This is in the form ax2+2bx+c=0)First divide 2b by 2 (4/2=2)Then put this into (x+b)2-(b)2+c=0This gives: (x+2)2-(2)2GJAnswered by George J. • Maths tutor2620 Views
16 = 2482x = (23)2x = 26xTherefore, 16x82x = 24x 26x = 24+6x
dy/dx = 20 - 2x - 6x2 = -6x2 - 2x + 20 which factorises to dy/dx = (10 - 6x)(2 + x). This shows that x=-2 and x=10/6=5/3 are stationary points of y = 20x −x2 −2x3XYAnswered by Xixi Y. • Maths tutor5759 Views
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