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y =(4x)/(x^2+5) (a) Find dy/dx, writing your answer as a single fraction in its simplest form. (b) Hence find the set of values of x for which dy/dx<0

dy/dx = 4/(x^2+5) - 4x(2x)/(x^2+5)dy/dx= 4(5-x^2)/(x^2+5)^2Part B4(5-x^2)/(x^2+5)^2<05-x^2<05<x^2

DK
Answered by Dominic K. Maths tutor
4115 Views

Factorise f(x)=3x^3+8x^2-20x-16 completely

First we need to use the factor theorem to find a factor.f(1)=-25 so x-1 is not a factorf(-1)=9 so x+1 is not a factorf(2)=0 so x-2 is a factorSo x-2 is our starting point, we need to polynomial division ...

LB
Answered by Luke B. Maths tutor
4633 Views

Solve the following simultaneous equations 7x - 6y =38 and 3x + 9y =-3

To solve these equations you first want to eliminate the same variable from each equation. In this question it is easiest to eliminate Y, to do this we will times equation 1 by 3 to get 21X-18Y=114 and eq...

IR
Answered by Isabelle R. Maths tutor
3175 Views

Write 16*8^2x as a power of 2 in terms of x.

Change 16 as a power of 2 to get 24. Change 82x as a power of 2 gives (23)2x. You can times the two powers together giving 26x.So 16*82x=2...

NA
Answered by Nabeel A. Maths tutor
13033 Views

Use the substitution u=cos(2x)to find ∫(cos(2x))^2 (sin(2x))^3dx

Step 1 differentiate substitution: du/dx = -2sin(2x)Step 2 rearrange for dx: dx=du/-2sin(2x)Step 3 substitute: integral= ∫u2sin3(2x).du/-2sin(2x)Step 4 get the integral in terms of u...

NA
Answered by Nabeel A. Maths tutor
6968 Views

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