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Differentiate y = 2e^(2x+1)

Hint: Use the chain rule

Answer: dy/dx = 4e^(2x+1)

MG
Answered by Matt G. Maths tutor
5095 Views

Solve the equation [(3x + 3)/2x] + 2x - 1 = -3

In this question we are trying to find all the possible solutions of the variable x that will satisfy the given equation. Firstly, we see there is a denominator on one of the terms so we multiply all the ...

CB
Answered by Chris B. Maths tutor
3165 Views

Solve x^2+6x+5=0 for x

x2+6x+5=(x+5)*(x+1)=0 therefore x+5=0 or x+1=0, hence x=-5 and x=-1

WR
Answered by William R. Maths tutor
2996 Views

Integrate y=x^2 between the limits x=3 and x=1

Integrate y=x^2 which is 1/3 x^3 Subsitute the limits, (1/3 (3)^3)-(1/3 (1)^3) 27/3 - 1/3 = 26/3

CW
Answered by Caleb W. Maths tutor
3551 Views

Given that y=((3x+1)^2)*cos(3x), find dy/dx.

As why is in the for y=uv where u and v are funtions of x, dy/dx=u'v+v'u (where ' implies the derivative) u=(3x+1)2, v=cos(3x) therefore using the chain rule u'=23(3x+1)=18x+6 and v'=-...

WR
Answered by William R. Maths tutor
3441 Views

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