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Solve 5x-2=3x+11

5x-2=3x+11

Move the (-2) to the right handside. As it crosses over the (-) becomes a (+)

5x=3x + (11+2)

Move the (+3x) to the left handside. As it crosses over the (-) becomes a (+)

Answered by Tom F. • Maths tutor

4082 Views

Consider f(x)=a/(x-1)^2-1. For which a>1 is the triangle formed by (0,0) and the intersections of f(x) with the positive x- and y-axis isosceles?

We'll first compute these intersections by setting x=0 and y=0 consecutively. This gives y=a-1 and a/(x-1)^2-1=0. Hence we find (x-1)^2=a, so x=1+-sqrt(a). As we have a>1 and we want the intersection w...

Answered by Ward V. • Maths tutor

3140 Views

How can you find the coefficients of a monic quadratic when you know only one non-real root?

We know that non-real roots appear in complex conjugate pairs. Hence when we know one root, we know both of them. Then, as we can factorise a quadratic in it's linear factors, we know our quadratic is a c...

Answered by Ward V. • Maths tutor

4032 Views

By consdering partial fractions find the integral of (1-x)/(5x-6-x^2) between x = 1 and x = 0, give your answer in an exact form.

The answer is Ln8/9, by first converting (1-x)/(5x-6-x^2) into partial fractions you get 1/(2-x) + 2/(x-3), the next step is a simple integration by inspection followed by log manipulations to get the fin...

Answered by Omar A. • Maths tutor

3004 Views

Re-arrange (3x+y)/2 = x+z making x the subject.

To make x the subject we want to try to get all the x's on one side of the equals sign! Firstly to get rid of the fraction we multiply both sides by 2, giving 3x+y= 2(x+z). We then expand the brackets on ...

Answered by Lara M. • Maths tutor

3189 Views