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I would go through one of the problem on the interactive board with the student and ask them to try next question alone.

The minimum value lies where the tangent to the curve has a gradient of zero and the curve approaching from both directions increases in value. This is done by finding the first and second derivatives of ...

1a) To simplify this into one expression you first multiply together the co-efficients, therefore 2a x a = 2a. Then for indices when they are multiplied together you add them, so the simplification would ...

Sub in f(x)=53 into equation. So you have 53=2x^2+3, deduct 3 from both sides to get 50=2x^2 and then divide each side by 2 to get 25=x^2 and finally square root both sides to get x=5 or x=-5.

3y-18x+9=0 , 3y=18x-9 , y=6x-3 , Both lines have the same value for m which means they both have the same gradient and are therefore parallel.