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Find dy/dx of the curve x^3+5xy-2y^2-57=0

3x2+5y+5x(dy/dx)-4y(dy/dx)=0

3x2+5y=(5x-4y)dy/dx

dy/dx=(3x2+5y)/(5x-4y)

SP
Answered by Steven P. Maths tutor
3844 Views

Given that y=x/(2x+5) find dy/dx.

Using the quotient rule: Let u=x and v=2x+5 then du/dx= 1 and dv/dx=2 Hence dy/dx=[(2x+5)x1- (2x)]/(2x+5)2             =5/(2x+5)2

SB
Answered by Shayna B. Maths tutor
3496 Views

Sam takes out a £720 loan. Sam will have to pay back the £720 plus an interest rate of 15%. He will have to pay this back in 12 equal monthly instalments. How much must Sam pay monthly?

First, you must find out the total amount to pay back, this amount will be £720 + 15% of £720. To find 15% of £720, we first calculate 720/100 to find 1% and the multiply by 15: 720/100 = 7.2 *15 = 108. N...

SN
Answered by Samuel N. Maths tutor
3717 Views

Integrate xsin2x

Integrate by parts: integral = [uv] - ∫u'v dx (u'= derivative of u, v'= derivative of v)

u= x     u'= 1

v' = sin2x        v= -0.5cos2x

= -0.5xcosx  -  ∫-0.5cos2x dx

= -0.5xcosx...

JE
Answered by Julia E. Maths tutor
19379 Views

What is the area bound by the x-axis, the lines x=1 and x=3 and the curve y=3x^(2)-1/x ? Answer in exact form.

Integrate, y= 3x-1/x

 1{3x- 1/x dx = [x-lnx]31= (3-ln3)-(1-ln1) = 3-ln3-1+0= 2-ln3

EL
Answered by Escher L. Maths tutor
3857 Views

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