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We are presented with a third order polynomial with 4 terms, so we expect 3 solutions for f(x)=0. To prove that (x-2) is a factor we must insert the value of x=2 into the function and if f(2)=0 then we ha...
L = (H2+R2)1/2 V = (1/3)πR2(H2+R2)1/2
dV/dt = -k
dH/dt = dH/dV × dv/dt
dV/dH = (1/3)πR2H(H...
∫ln(x)dx = xln(x) - ∫x/x dx = xln(x) - x + C
Multiply the first equation by 2, and the second by 3:
6x+10y=14
6x-9y=33
Subtract the second from the first:
19y=-19
solve for y:
y=-1
plug in to first eq...
Any constant (say k) can be rewritten as kx0 since x0=1. When you differentiate this, the 0 which is the power of the x term gets dragged to the front and is multiplied with the rest...
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