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Given that, dy/dx = 6x^2 - 3x + 4, and y = 14 when x = 2, express y in terms of x.

dy/dx = 6x2 - 3x + 4
To retrieve the original function y from dy/dx you have to integrate the derivative with respect to x.
y = ∫(dy/dx)dxy = ∫(6x2 - 3x + 4)dx
To inte...

CB
Answered by Ciaran B. Maths tutor
5929 Views

Do the circles with equations x^2 -2x + y^2 - 2y=7 and x^2 -10x + y^2 -8y=-37 touch and if so, in what way (tangent to each other? two point of intersection?)

We must first complete the square for both equations and get the equations in the (x-a)2+(y-b)2=r2 with the primary objective of determining the centres of both circles (a...

SS
Answered by Shanti S. Maths tutor
3591 Views

Factorise x^2 - 6x + 9 = 0

x2 - 6x + 9The method for factorising quadratics is to find 2 numbers that add to make the 'x' term (-6x in this case), and multiply together to make the final term (+9 in this case). Factors o...

KB
Answered by Kate B. Maths tutor
8281 Views

What is 64^1/2 equal to?

A number to the power of 1/2 is the same as square rooting (√) the number, therefore 641/2 is equal to √64.Remember that it can be the positive or the...

KB
Answered by Kate B. Maths tutor
26087 Views

Differentiate f(x)= 3y^2 + ln (x) + sin x

We have derivative rules. Some of them involve:If f(x)= (x)a=> f'(x)= a*xa-1If f(x)= ln x=> f'(x)= 1/xIf f(x)= sin x=> f'(x)=cos xTherefore, f(x)= 6y+1/x+cos x

DC
Answered by Daria C. Maths tutor
1447 Views

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