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Here we have two equations with two unknowns, the method we use to solve this is substitution. First, find one of the unknowns in terms of the other by rearranging the first equation to arrive at y = 3x -...

Rearrange the second equation in terms of y: meaning that the equation is of the form y = ....-this will give y = 3 - x/2You may now substitute the y in the left hand equation with what y in the right han...

First we must expand the demoninator to; (x+3)(x-3)Then we can multiply the left hand fraction on top and bottom by (x-3) to get a common demoninatorthis gives us; (4x)/((x+3)(x-3)) - ((2)(x-3))/((x+3)(x-...

There are 2 ways to solve this equation:Method 1:Expand the brackets by multiplying everything inside the brackets by 4 to make 4x-20=18Then +20 to both sides making 4x=38Then divide by 4 to find x, there...

The important point in the question is the term 'stationary point'. This is where the graph of y will 'flattern out'. If we look at this graph, we can say that the gradient is equal to 0 at this point. Th...