A curve has the equation: x^3 - x - y^3 - 20 = 0. Find dy/dx in terms of x and y.
x3 - x - y3 - 20 = 0 Find dy/dx. Differentiate with respect to x.
3x2 - 1 - 3y2(dy/dx) = 0Therefore: dy/dx = (3x2 - 1)/3y2
KP
x3 - x - y3 - 20 = 0 Find dy/dx. Differentiate with respect to x.
3x2 - 1 - 3y2(dy/dx) = 0Therefore: dy/dx = (3x2 - 1)/3y2
