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c = 4-d/d+3 x d+3 = c(d+3)= 4-d = cd +3c= 4- d = cd+d=4-3c. = d(c+1)=4-3c = d= 4-3c/c+1

From the properties of logarithms (log_ba = log_ca / log_cb), 10log₉6 can be rewritten as 10(log₃6 / log₃9). Since log₃9 = 2, 10lo...

(1) Find the Midpoint of PQ which is (1,2) (Halfway between the x and y coordinates)(2) dy/dx for M(1,2) -> R(3,6) = (6-2)/(3-1) = 4/2 = 2(3) y =mx + c so y = 2x + c when R(3,6) is input 6 = 2(3) + c, ...

Differentiating x² gives dx²/dx=2x. Differentiating a constant C gives 0. d( x² +C)/dx=dx²/dx+dC/dx=2x+0=2x. Since integration is the inverse function of differ...

To find the stationary points of the curve y(x), you must first differentiate the equation for y(x) in terms of x. This gives d(y(x))/dx = x^2 -5x +4. Now set this differential equal to zero and solve for...