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Using methods of substitution solve the following simultaneous equations: y - 2x - 1 = 0 and 4x^2 + y^2 - 25 = 0

(1) 4x2 + y2 - 25 = 0 (2) y - 2x - 1 = 0
Rearranging (2) into an equation of y in terms of x we have:y = 2x +1
now substituting into equation (1) 4x2 + (2x +1)...

KM
Answered by Kerry M. Maths tutor
3564 Views

Solve the equation 2y^(1/2) -7y^(1/4) +3 = 0

2y1/2 -7y1/4+ 3 = 0 We need to use a substitution to obtain a quadratic.Let y1/4 = x (use the y with the smallest fractional power as your substitution)From this, we can s...

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Answered by Sarah L. Maths tutor
6315 Views

Using the product rule, differentiate y=(2x)(e^3x)

The product rule states that if y=uv, where u and v are both functions of x, then dy/dx = u(dv/dx) + v(du/dx)Therefore, the differential of 2xe3...

CO
Answered by Christy O. Maths tutor
6701 Views

Amanda and Wim share some money in the ratio 2:5. Wim receives £115. Calculate how much money was shared?

First, you need to find value of one part. We can see that Wim who has a share of 5 parts gets £115. So, 5 parts is equivalent to £115. Therefore, value of each part is 115/5 = £23. Now,...

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Answered by Saeideh N. Maths tutor
12491 Views

rearrange c=(4-d)/(d+3)

c = 4-d/d+3 x d+3 = c(d+3)= 4-d = cd +3c= 4- d = cd+d=4-3c. = d(c+1)=4-3c = d= 4-3c/c+1

VY
Answered by Verina Y. Maths tutor
7427 Views

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