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Integrate y=x^2 which is 1/3 x^3 Subsitute the limits, (1/3 (3)^3)-(1/3 (1)^3) 27/3 - 1/3 = 26/3

As why is in the for y=uv where u and v are funtions of x, dy/dx=u'v+v'u (where ' implies the derivative) u=(3x+1)², v=cos(3x) therefore using the chain rule u'=23(3x+1)=18x+6 and v'=-...

x² - 10x + 33 ≡ (x - a)² + b Work out the value of a and b. Our aim here is to write the expression on the left in the same form as the one on the...

First you need to remove the fractions from each side,

take the equation: (x+1)/(x+3) = (2x-1)/(3x-1)

now multiply by x+3 to give x+1 = (2x-1)(x+3)/(3x-1)

now multiply by (3x-1) to gi...

written out