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The main piece of information this question gives us is that the two lines do not cross or touch. From this we can immediately see that we will need to use the discriminant of the quadratic formula b^...

In order to solve this question we simply must substitute x=1 into f(x).

If we carry out this substitution we see that

f(1) = 2(1^3) + (1^3) -5(1) + c = 2(1) + (1) -5(1) + c = 2 + 1  - 5 + c...

Let's reorgansie the information we've been provided with in the question: Colour of marble - number of marbles in the bag Blue - 2x Green - 7 Red - 7x + 5 Orange - 4x - 3 Probability of the green marble ...

Factorise the numerator: x^2 + x - 6 = (x+3)(x-2)

Factorise the denominator: 3x^2 + 9x = 3x(x+3)

Cancel '(x+3)'

Answer: (x-2)/3x

sin^2(x) + sin(x) + cos^2(x) + cos(x) = cos(x)sin(x) + cos(x) + sin(x) +1

(sin^2(x) + cos^2(x) =1) Therefore;

1 +sin(x) + cos(x) = cos(x)sin(x) + sin(x) +cos(x) +1

Cancelling out on b...