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Two methods for simultaneous equations: making them equal to each or substitution. If they both have a common term, for example "y", then you can do substitution, otheriwise find a way to make t...

-Tangent is a straight line that touches, but does not intersect, the curve at the point (2,8).

We need to find the gradient of the curve at the point (2, 8). To do this, expand the equation, diffe...

To solve this we must use the chain rule which is dy/dt * dt/dx. Firstly, we differentiate dy/dt. For this we must use the quotient rule, this gives us dy/dt=(9te^3t - 3e^3t)/9t^2. Now for dx/dt, by subst...

Student should factorise equation to (x-2)(x+3) = 0 This gives roots of 2 and -3

Solving a simultaneous equation finds the point(s) where two lines on a graph intercept. Therefore, one way of solving the equations is to plot the two lines onto the same graph and find the coordinates o...